Solving Systems By Substitution

Given 2 equations:

1. Solve both equations in terms of y= ax+b.
Example:
4x + 2y = 12 and 6x - 2y = 16
(Move all x's to right side of equation)
2y = -4x + 12 and -2y = -6x + 16
(Divided by coefficient of y) = (Coefficient of y is the number in front of y)
y = -2x + 6 y = 3x - 8

2. Set the two equations equal to each other and solve for x.
Example:
-2x + 6 = 3x - 8
(Moved all x's to right side of equation)
6 = 5x - 8
(Moved all numbers to left side of equation)
14 = 5x
(Divided by coefficient of y)
14/5 = x
2.8 = x (14 divided by 5 equals 2.8)

3. Choose one of the equations produced in part 1 and substitute the solution for x in place of any x in the equation.
Example:
y = -2x + 6
y = -2*2.8 + 6
y = -5.6 + 6
y = 0.4

4. Solution is coordinate point (x, y)
Example:
(2.8,0.4)